9
$\begingroup$

How do I get the equivalent of the $\LaTeX$ \tag{} in Mathematica?

$a+b=x \tag{1}$

I'm not necessarily asking how to use the $\LaTeX$ \tag{} itself in Mathematica, I'm just looking for some feature that will allow me to mark an equation like that.

$\endgroup$
  • 1
    $\begingroup$ CellLabel gets close but as Right is not a valid setting for CellLabelPositioning it cannot, AFAIK, be made to look as you show. $\endgroup$ – Mr.Wizard Jan 6 '13 at 7:31
  • $\begingroup$ There's also the Automatic Numbering. $\endgroup$ – Billy Rubina Jan 6 '13 at 7:34
9
$\begingroup$

I do not think what you are asking for is possible. But you can do what you want by numbering an equation in Mathematica like this

Mathematica graphics

do not know if this will meet your needs.

Using Mathematica like Latex is not really practical or useful. I found it is better to just use Latex for typesetting, and use Mathematica for doing the computation and analysis.

$\endgroup$
  • $\begingroup$ Yes. But I wasn't expecting to use $\LaTeX$ to do that. I was expecting for any alternative that would lead me to do that. Thanks for the answer. $\endgroup$ – Billy Rubina Jan 6 '13 at 7:40
10
$\begingroup$

As others have pointed out, automatic numbering is nicely taken care of through the built-in DisplayFormulaNumbered style. Custom numbering (both a separate counter and counting sequence) can be introduced into stylesheets, for example, I have made a Theorem style before.

However, for a one off equation numbers / labels, like the $\LaTeX$ \tag option, you just want to manually set the CellFrameLabels option. This can be done using the option inspector or by using CellPrint or Show Expression. For example

CellPrint[Cell[BoxData[
   FormBox[RowBox[{"a", "+", "b", "=", "c"}], TraditionalForm]], 
  "DisplayFormula", CellFrameLabels -> {{None, "(1a)"}, {None, None}}]]

produces
a+b=c
selecting the cell and looking at the option inspector shows you how you could edit this option with a GUI:

option inspector


However, referring to that equation using the standard CellTags and Automatic Numbering / CounterBox combination seems to be a bit tricky... There might be a nice way of doing it, but nothing immediately comes to mind.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.