I am trying to solve following PDE using DSolve but there is no result upon completion-

DSolve[D[-A[r,t],t]D[A[r,t],r]+A[r,t]D[D[A[r,t],r],t]==0,A[r, t], {r, t}]
  • $\begingroup$ DSolve[]'s support for PDE's is still somewhat limited, so don't be surprised if some things don't work yet :P. Try alternative -> Maple. $\endgroup$ Feb 9 '18 at 12:59
  • $\begingroup$ The approach A[r,t]=R[r]T[t](separation of variables) solves the pde without any restriction concerning R[r],T[t] ??? $\endgroup$ Feb 9 '18 at 13:04

Your pde leads to $1=1$. So any two random functions $R(r)$ and $T(t)$ give a solution.

Solve $$ -u_{t}u_{r}+u\ u_{rt}=0 $$

Let $u=R\left( r\right) T\left( t\right) $ then the above becomes

\begin{align*} -\left( RT^{\prime}\right) \left( R^{\prime}T\right) +\left( RT\right) \ \left( R^{\prime}T^{\prime}\right) & =0\\ R^{\prime}T^{\prime} & =R^{\prime}T^{\prime}\\ 1 & =1 \end{align*}

So try any random functions, $R(r)$ and $T(t)$, they will be a solution

   u=R0 T0;     
   Simplify[D[-u,t]D[u,r]+u D[D[u,r],t]]

 (* 0 *)

 (* 0 *)

 solvePDE[r^3, t^8, r, t]
 (* 0 *)

May be Mathematica should just have returned $F1(r) F2(t)$ as an answer?


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