Good morning,
I want to find a solution to the following equation:
$$\left|u\cdot\sin\left(2\pi\cdot f\cdot t\right)\right|=u\cdot\exp\left(-\frac{t}{a}\right)\space\Longleftrightarrow\space t=\dots\tag1$$
The sine-function is a periodic function, so I want only one solution and that is the solution that is between the follwing boundaries:
$$\frac{1}{2\cdot f}<t<\frac{3}{4\cdot f}\tag2$$
Now, alle the variables are real numbers and bigger than zero.
Question: How can Mathematica 10.0 solve this question? Or approximate the solution?