I am trying to do the following :
How do I obtain an expression for $\epsilon$
0
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3
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Using Format
Format[σ0] = Subscript["σ", 0];
Format[ϵ0] = Subscript["ϵ", 0];
σ = σ0/(1 - I ω τ);
ϵ = ϵ0 (1 + I σ/(ω ϵ0));
Simplify@ϵ
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Simply, subscripts don't work like that in Mathematica. When you define $\epsilon=\epsilon_\theta$, the $\epsilon$ on the right hand side is then substituted with the definition, because $\epsilon_\theta$ is not actually treated as its own variable.
σ = σθ (1 - I ω τ);
ϵ = ϵθ (1 +
I σ/(ω ϵθ));
Simplify[ϵ]
ϵθ + σθ (τ + I/ω)
Please also note that Simplify ϵ is literally interpreted as Simplify times ϵ, and will not result in any simplification. The square brackets are necessary for Simplify to have any effect.
Please also note that as written in your screenshot, the imaginary unit I will not be evaluated, as it is part of a variable name. To multiply I by something, make sure there is a (space) or * (asterisk) between them.
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$\begingroup$ But I want the Sigma from equation 1 to be substituted into equation 2. $\endgroup$ – Indeterminate Feb 6 '18 at 23:27
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1$\begingroup$ Then put a space between the imaginary unit and the sigma, otherwise it's one variable. Will edit that in momentarily. $\endgroup$ – eyorble Feb 6 '18 at 23:29
Simplify[ ]. And there is no reason your Simplify call "knows" the first definition you've given. $\endgroup$ – David G. Stork Feb 6 '18 at 23:20