0
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This statement:

Simplify[Minimize[{Exp[3 q], q >= 0}, q]]

Returns correctly:

{1, {q -> 0}}

But this statement:

Assuming[n > 1, Simplify[Minimize[{Exp[n q], q >= 0}, q]]]

returns:

Minimize[{E^(n q), True}, q]

Am I doing anything wrong? Or is Mathematica just unable to handle the extra parameter?

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  • $\begingroup$ Set n also as the target variable of Minimize: Minimize[{Exp[n q], q >= 0, n >1}, {q, n}]. $\endgroup$ – Αλέξανδρος Ζεγγ Jan 29 '18 at 13:39
  • $\begingroup$ @AlexanderZeng this gives a specific value for $n$: {1, {q -> 0, n -> 2}}. But the minimization of $q$ is actually true for every $n>0$... $\endgroup$ – Erel Segal-Halevi Jan 30 '18 at 6:58

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