# How to understand the results of solve:ifun? [duplicate]

• When you see a message like this, click the ..., then the documentation link that appears. For this message, everything is explained there. – Szabolcs Jan 10 '18 at 9:37
• Thank you! The code is as follow: RR[ρ_]:= b (1+k) (2+k) ρ ((b/(1+ρ))^(1/(2+k)))^(-1-k) (-α+(b/(1+ρ))^(1/(2+k)))+(b/(1+ρ))^(1/(2+k)) (1+ρ) ((3+2 k) α-2 (1+k) (b/(1+ρ))^(1/(2+k)))+2 (1+k) (b/(1+ρ))^(1/(2+k)) (-1+ρ^(1+k)) ((2+k-2 ρ) (b/(1+ρ))^(1/(2+k))+α (-2-k+ρ)). It's essentially trying to solve out \rho in terms of all other parameters. But I guess it's unlikely to obtain analytic solution in this case. – Joseph Martin Jan 12 '18 at 0:16