How to plot $(x,y)$ phase diagram?

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Asked 6 years, 9 months ago

Modified 6 years, 9 months ago

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I would like to plot the $(x,y)$ phase diagram under this constraint: $$-\frac{x}{3} - \sqrt{\left( \frac{x}{3} \right)^2 - \frac{y}{6}} = 0$$

I tried to use ContourPlot

ContourPlot[-x/3 - Sqrt[(x/3)^2 - y/6], 
       {x, -10, 10}, {y, -10, 10}]

David G. Stork

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asked Nov 28, 2017 at 4:53

0x90

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$\begingroup$ ContourPlot[-x/(3) - Sqrt[(x/(3))^2 - y/(6)] == 0, {x, -10, 10}, {y, -10, 10}] would just give you only one contour. $\endgroup$
– Αλέξανδρος Ζεγγ
Commented Nov 28, 2017 at 6:09
$\begingroup$ Solution of this equation is y=0 at x<=0. Are you sure that this describes a phase diagram? $\endgroup$
– Alexei Boulbitch
Commented Nov 28, 2017 at 8:53
$\begingroup$ What does this have to do with phase or phase diagrams? $\endgroup$
– David G. Stork
Commented Nov 28, 2017 at 17:31

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