2
$\begingroup$

Is there a way to extract boundary surface from a 3d region plot? I've plotted my equations using:

kSimplified = 
  (1 + x + y + 2 x y + x^2 y + x y^2 + x^2 y^2 - z + 2 x^2 y z + 
    x^2 y^2 z - x z^2 + x^2 y z^2) /
  (y (1 + z) (1 + y + x y - z + x y z));
aSimplified = 1 + y + x y - z + x y z;
RegionPlot3D[
  kSimplified > 0 && aSimplified > 0, {x, 0, 2}, {y, 0.00001, 2}, 
  {z, 0, 5}]

Is there any way to extract the orange part from my plot(picture below)? Or is there any smarter way to get that boundary surface?

The resulting plot is this: enter image description here

$\endgroup$
  • $\begingroup$ Maybe with ContourPlot3D... $\endgroup$ – Henrik Schumacher Nov 27 '17 at 22:02
  • 1
    $\begingroup$ Try ContourPlot3D[{1 + y - z + x^2 y (1 + z) (1 + y + z) + x (1 + 2 y + y^2 - z^2) == 0}, {x, 0, 2}, {y, 0.00001, 2}, {z, 0, 5}, PlotPoints -> 50, Mesh -> None] $\endgroup$ – José Antonio Díaz Navas Nov 27 '17 at 22:22
  • $\begingroup$ That did the trick. Thank you! $\endgroup$ – DiracDog Nov 28 '17 at 0:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.