# Alternative for Nsolve

I have an optimization problem for this 4 bar-linkage.

Nothing is known(a,b,c,d,x,y) except The Tip of the triangle's co-ordinate which is known for some value of phi (angle between a and d). For Example when phi is 0 Trangle tip is at (1.22,3.66) See the table below.

The system of equation I ended up with is known as Freudenstein equation:

φ[ϕ_, a_, b_, c_, d_] :=
ArcSec[(2 c^2 (d - a Cos[ϕ]) (a^2 + d^2 -
2 a d Cos[ϕ]))/(c (d - a Cos[ϕ])^2 (a^2 - b^2 +
c^2 + d^2 - 2 a d Cos[ϕ]) -
a c √(-(d -
a Cos[ϕ])^2 (a^4 + (b - c - d) (b + c - d) (b - c +
d) (b + c + d) - 2 a^2 (b^2 + c^2 - 2 d^2) +
2 a d (2 (-a^2 + b^2 + c^2 - d^2) Cos[ϕ] +
a d Cos[2 ϕ]))) Sin[ϕ])];

A[ϕ_, a_] := a {Cos[ϕ], Sin[ϕ]};

B[ϕ_, a_, b_, c_, d_] := {d - c Cos[φ[ϕ, a, b, c, d]],
c Sin[φ[ϕ, a, b, c, d]]};

λ[ϕ_, a_, b_, c_, d_] := ArcTan @@ (B[ϕ, a, b, c, d] - A[ϕ, a]);

W[ϕ_, a_, b_, c_, d_] := A[ϕ, a] + x {Cos[λ[ϕ, a, b, c, d] + y],
Sin[λ[ϕ, a, b, c, d] + y]};


Should look like this picture if you run the code on Mathematica

Then I run this code to get 24 equation for the triangle tip co-ordinate(see the 2nd image (phi, x, y table ))

System = W[#, a, b, c, d] & /@ {0, π/6, π/3, π/2, (
2 π)/3, (5 π)/6, π, (7 π)/6, (4 π)/3, (
3 π)/2, (5 π)/3, (11 π)/6} // Simplify // Flatten


The problem is when I am trying to solve this using

NSolve

NSolve[System == {1.22, 3.66, 0.9, 2.7, 1.2, 1.93, 1.93, 1.48,
3.1, 1.46, 4.58, 1.85, 5.8, 2.36, 6.12, 3.2, 5.62, 4.06,
4.57, 4.8, 3.24, 4.9, 2.04, 4.45}, {x, y, a, b, c, d}, Reals]


It runs for eternity. Can any one tell me if I have any other option to solve this in Mathematica? Thanks

Update The table has changed because I made a mistake, instead of taking phi from 0-360, I took it from 0-180. The table has been changed. so Is the corresponding code(code block 2)

• You can try FindRoot if you know some initial guess. Nov 22, 2017 at 10:58
• Reduce is generally the most powerful equation solving function in Mathematica. Be sure to add constraints if you have any. (e.g, all your variables are positive; that's useful to include in the problem). Short of that: like the above comment says, try FindRoot with an initial guess. Nov 22, 2017 at 16:52

J=Sum[#.#&[ {xModel[PHI,para],yModel[PHI,para]}-{xTable[PHI],yTable[PHI}],{PHI}]