# Plotting a function with different parameters sets [closed]

Plot $f(r) = - a/r^2-b/r^3$ for the three parameter sets (a=1, b=1), (a=-1, b=-1), (a=0, b=1) in a single plot. The three cases should each be a different color and labeled with its associated parameter set (r ranges from 0 to 10).

I need help with making the plot.

## closed as off-topic by Artes, LCarvalho, MarcoB, Henrik Schumacher, gwrNov 24 '17 at 22:37

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f[a_, b_, r_] = -a/r^2 - b/r^3
Plot[{f[1, 1, r], f[-1, -1, r], f[0, 1, r]}, {r, 1, 10},PlotLegends->{"1,1","-1,1","0,1"}]


Based on Sumit's solution, but offering a differing labeling scheme based on the fairly new option PlotLabels, which I think work better than legends for this plot.

f[a_, b_, r_] = -a/r^2 - b/r^3
Plot[{f[1, 1, r], f[-1, -1, r], f[0, 1, r]}, {r, 1, 10},
PlotLabels -> {"(a=1, b=1)", "(a=-1, b=-1)", "(a=0, b=1)"}]


### Update

I got to thinking that it would be nice to have an implementation that would work for a general list of parameter pairs. This is what I came up with.

With[{params = {{-1, -1}, {-1, 0}, {-1, 1}, {1, -1}, {1, 0}, {1, 1}}},
Module[{avals, bvals, curves, lbls, items},
{avals, bvals} = Transpose @ params;
curves = MapThread[-#1/r^2 - #2/r^3 &, {avals, bvals}];
lbls = MapThread[Row[{" a=", #1, ", b=", #2}] &, {avals, bvals}];
items =