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I have list functions which have two variables. I want to plot the list in terms of one variable and show effects of the other variable on the plots using Manipulate or Animate command of Mathematica. After I did it, nothing was plotted and I could not figure it out this problem. It's kind of you if you help me. In the following the code has been brought.

thelist = Table[n = 0;
L = 2;
τ = 2;
ε = (1/2)((N[BesselJZero[
     Sqrt[(χ - 3/2)^2 + (χ*L*(L + 1))/3 + τ*(τ + 3)*(1 - χ)
], n + 1]])^2 - α m), {m, -2, 2, 1}];

Manipulate[ 
  Plot[thelist, {α, 0, 1}
  , PlotLegends -> {"m=-2", "m=-1", "m=0", "m=1", "m=2"}
  , PlotStyle -> {Green, Black, Yellow, Blue, Red}
  ]
, {χ, 0, 1}
]
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1 Answer 1

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Here is a work around. Something strange is happening. But this makes it work. It might be the strange variable name you used [Chi] ? I do not know why. But adding new control variable z and then using this made it work.

enter image description here

thelist = Table[n = 0;
   L = 2;
   \[Tau] = 2;
   \[CurlyEpsilon] = (1/
       2) ((N[BesselJZero[
           Sqrt[(\[Chi] - 3/2)^2 + (\[Chi]*L*(L + 1))/
              3 + \[Tau]*(\[Tau] + 3)*(1 - \[Chi])], 
           n + 1]])^2 - \[Alpha] m), {m, -2, 2, 1}];

Manipulate[
 Plot[Evaluate[thelist /. \[Chi] -> z], {\[Alpha], 0, 1}, 
  PlotLegends -> {"m=-2", "m=-1", "m=0", "m=1", "m=2"}, 
  PlotStyle -> {Green, Black, Yellow, Blue, Red}, 
  AxesOrigin -> {0, 23}],
 {z, 0, 1, Appearance -> "Labeled"}
 ]
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  • $\begingroup$ Thanks, dear Nasser. Your suggestion was simple and it worked out. $\endgroup$
    – AYBRXQD
    Nov 13, 2017 at 6:01
  • $\begingroup$ Isn't it mathematica.stackexchange.com/q/10604/5478 or any of linked closely related ones? $\endgroup$
    – Kuba
    Nov 13, 2017 at 8:10
  • $\begingroup$ @Kuba I have not see the question you linked to before. If you think it is duplicate question, please feel free to close this as duplicate. $\endgroup$
    – Nasser
    Nov 13, 2017 at 8:41
  • $\begingroup$ @Nasser it is very close but I believe there is a better one somewhere. I don't have time to search so I will leave it with peace :) $\endgroup$
    – Kuba
    Nov 14, 2017 at 7:54

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