I know that you can generate an $m\times n$ matrix of random numbers by RandomReal[range, {m, n}], where e.g. range = {0, 1}.

Is there a way to generate an $m\times n$ matrix of random numbers and have each column entry be drawn from a different range?

My question is, if there is something analogous to RandomReal[{range1,range2,...,rangen},{m,n}] (which obviously does not evaluate because it is not supported).

My current solution to this problem is using Map; i.e.


where m is the desired number of $n$-tuples of random numbers from $n$ different ranges that I need.

Is there a better alternative to this?


1 Answer 1


The simplest way is to use UniformDistribution[] in RandomVariate[]:

BlockRandom[SeedRandom[42]; (* for reproducibility *)
            RandomVariate[UniformDistribution[{{3, 4}, {5, 7}}], 4]]
   {{3.42591, 6.11193}, {3.39102, 5.57834}, {3.34707, 5.5937}, {3.45374, 5.41282}}

Alternatively, you can use RescalingTransform[] on the results of RandomReal[]:

scaledRandomReal[ranges_?MatrixQ, n_Integer] := With[{m = Length[ranges]}, 
      RescalingTransform[ConstantArray[{0, 1}, m], ranges][RandomReal[1, {n, m}]]]

BlockRandom[SeedRandom[42]; scaledRandomReal[{{3, 4}, {5, 7}}, 4]]
   {{3.42591, 5.78205}, {3.34707, 5.90748}, {3.55596, 5.57834}, {3.29685, 5.41282}}
  • $\begingroup$ Are there advantages to the first form (RandomVariate[UniformDistribution[...) over Transpose[RandomReal[#,4]&/@{{3,4},{5,7}}]? $\endgroup$
    – orome
    Commented Nov 1, 2017 at 12:55
  • $\begingroup$ Yes, that works too. I just didn't want to use slots. $\endgroup$ Commented Nov 1, 2017 at 13:14
  • $\begingroup$ I think I'll use UniformDistribution because it's easier to wrap my head around it; RescalingTransform is really interesting and it's kind of embarrassing not knowing anything about it even though it's a 10 years old feature; +1 for the people at Wolfram $\endgroup$
    – user42582
    Commented Nov 2, 2017 at 8:08

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