2
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 p11[x_, δ_, b11_] := 1/x^4 + (2 b11)/x^2 + 4/x - 4 b11 x - 
  1/(1 + (-1 + x^3) (1 + δ)^3)^(4/3) - (
  2 b11)/(1 + (-1 + x^3) (1 + δ)^3)^(2/3) - 
  4/(1 + (-1 + x^3) (1 + δ)^3)^(1/3) + 
  4 b11 (1 + (-1 + x^3) (1 + δ)^3)^(1/3)
Plot3D[p11[x, 0.01, b11]/0.01, {x, 1, 4}, {b11, 0, 0.5}, 
 Boxed -> False, AxesLabel -> {x, b11, p}, Mesh -> 5, 
 PlotLegends -> Automatic, BoundaryStyle -> Thick, AxesStyle -> Black,
  ViewPoint -> {-1.2, -2, 1.5}, 
 Ticks -> {{0, 2, 4}, Automatic, {5, 10}}, BoxRatios -> {1, 1, 1}]

enter image description here

Q:I want to show the maximum(or the peak) in red color, and the minmum(or the Valley) in blue.

color the local maximum region and the local minimum region

I want to see the location of the vally in colors, and how it changes with b11. I wonder if ColorFunction can do this? Can MMA color the nearby area of local extreme value in different color with others?

enter image description here

just like this

enter image description here

The extremum can be found like this Abs[D[p11[x, 0.01, b11], x]]=0.

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  • 1
    $\begingroup$ You could use something like Show[(* plot *), Graphics3D[{{Red, Sphere[(* max location *), 0.02]}, {Blue, Sphere[(* min location *), 0.02]}}]]. $\endgroup$ – J. M. will be back soon Oct 25 '17 at 8:41
  • $\begingroup$ Thank you for your suggestion! But I want to know how the function p[]-x change with b11 from 3Dplot, not the number solutions. $\endgroup$ – keanhy Oct 25 '17 at 9:23
  • 1
    $\begingroup$ Now what you sought, but I prefer: ColorFunction -> "Rainbow". $\endgroup$ – David G. Stork Oct 25 '17 at 15:19
  • $\begingroup$ Related question: mathematica.stackexchange.com/q/94595 $\endgroup$ – m_goldberg Oct 25 '17 at 16:27
  • 2
    $\begingroup$ You don't have local extrema in the regions you outline $\endgroup$ – m_goldberg Oct 26 '17 at 2:32
3
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p3d = Plot3D[p11[x, 0.01, b11]/0.01, {x, 1, 4}, {b11, 0, 0.5}, 
     Boxed -> False, AxesLabel -> {x, b11, p}, Mesh -> 5, 
     PlotLegends -> Automatic, BoundaryStyle -> Thick, 
     AxesStyle -> Black, ViewPoint -> {-1.2, -2, 1.5}, 
     Ticks -> {{0, 2, 4}, Automatic, {5, 10}}, BoxRatios -> {1, 1, 1}];

{min, max} = #[p3d[[1, 1]], Last] & /@ {MinimalBy, MaximalBy};
Show[p3d, Graphics3D[{PointSize[.05], Blue, Point@ First @ min, Red, Point@ First @ max}]]

enter image description here

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  • $\begingroup$ Better to use Sphere than Point in 3D don't you think? $\endgroup$ – m_goldberg Oct 25 '17 at 16:23
  • $\begingroup$ @m_goldberg, I agree; but plain Sphere gives ellipsoids, and felt lazy to find the right values for the second argument:) $\endgroup$ – kglr Oct 25 '17 at 16:31
  • $\begingroup$ In such cases I use Ellipsoid to adjust the markers to spherical. $\endgroup$ – m_goldberg Oct 25 '17 at 16:36
  • $\begingroup$ Sorry about my bad description, I just redescribe the question. Can MMA color the nearby area of local extreme value in different color just like the third picture? $\endgroup$ – keanhy Oct 26 '17 at 1:48
3
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The plot really looks better with spheres marking the extrema. And since kglr doesn't want to take the time to write the code to make such markers, I will will supply it.

p11[x_, δ_, b11_] := 
  1/x^4 + (2 b11)/x^2 + 4/x - 4 b11 x - 1/(1 + (-1 + x^3) (1 + δ)^3)^(4/3) - 
  (2 b11)/(1 + (-1 + x^3) (1 + δ)^3)^(2/3) - 4/(1 + (-1 + x^3) (1 + δ)^3)^(1/3) + 
  4 b11 (1 + (-1 + x^3) (1 + δ)^3)^(1/3)

surface = 
  Plot3D[p11[x, 0.01, b11]/0.01, {x, 1, 4}, {b11, 0, 0.5},
    Boxed -> False, AxesLabel -> {x, b11, p}, Mesh -> 5, 
    PlotLegends -> Automatic, BoundaryStyle -> Thick, 
    AxesStyle -> Black, ViewPoint -> {-1.2, -2, 1.5}, 
    Ticks -> {{0, 2, 4}, Automatic, {5, 10}}, BoxRatios -> {1, 1, 1}]

{min, max} = 
  Chop[#[surface[[1, 1]], Last] & /@ {MinimalBy, MaximalBy}, 10^-5][[All, 1]]

extrema =
  With[{r = .03 (max - min)}, 
    Graphics3D[{Blue, Ellipsoid[min, r], Red, Ellipsoid[max, r]}]];

Show[surface, extrema, PlotRange -> All]

plot

r is computed from the formula

 r = scaleFactor {xRange, yRange, zRange} = scaleFactor (max - min)

where scalarFactor is picked by eye.

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