I have a simple task of plotting the solution to a differential equation under different conditions and can't figure it out.

The solution is


and I need to plot it for 0

f[t_, b_] := [(e^(-b*t))[Cos[t] + b*Sin[t]], 
 t, {t, 0, 20}]

and I think something is wrong in my syntax. I will appreciate any guidance!

  • $\begingroup$ You have to use brackets instead of parentheses for arguments. Moreover, you might want Sin and Cos instead of sin and cos. Mathematica is case sensitive. $\endgroup$ – Henrik Schumacher Oct 22 '17 at 0:13

Maybe you are looking for something like this:

x[t_, b_, w_] := Exp[-b t] (Cos[w t] + b t Sinc[w t])
 Plot[x[t, b, w], {t, 0, 20}, PlotRange -> {-2, 2}],
 {{b, .1}, -2, 2},
 {{w, 1.}, -2 Pi, 2 Pi}

If you have specific values for b to plot, you can use, e.g.,

Plot[{f[t,0],f[t,0.1],f[t,1.]}, {t, 0, 20}]
  • $\begingroup$ So I did this, f[t_, b_] := Exp[b t] (Cos[t] + b*Sin[t]) which worked great for my function, but them plotting I don't get anything on the plot. I don't want to use the manipulate function because I want to pick specific values for b. $\endgroup$ – K. Schneider Oct 22 '17 at 0:39
  • $\begingroup$ How did you plot then? Note that b needs a specific value if want to use Plot[f[t,b],{t,0,20}]. $\endgroup$ – Henrik Schumacher Oct 22 '17 at 0:40
  • $\begingroup$ Plot[f[t], {t, 0, 20}] $\endgroup$ – K. Schneider Oct 22 '17 at 1:02
  • $\begingroup$ I am trying to figure out how to include b; I need it at specific values of 0, 0.1, and 1. $\endgroup$ – K. Schneider Oct 22 '17 at 1:04

If you just want plots for b from 0 to 1, you can do this

f[t_, b_] := Exp[-b t] (Cos[t] + b*Sin[t])

Table[Plot[f[t, b], {t, 0, 20}, PlotRange -> All, 
PlotLabel -> "b=" + b], {b, 0, 1, .1}]

but as above, Manipulate works too if you just want to vary b.

Manipulate[Plot[f[t, b], {t, 0, 20}, PlotRange -> {-1, 1}, 
  PlotLabel -> "b=" + b], {b, 0, 1, .1}]

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