This question already has an answer here:
Assume we have this For loop:
For[i=1,i<10,i++, i^2].
How can we put the squared values i^2 into a list?
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marked as duplicate by Simon Woods, corey979, Szabolcs, m_goldberg, MarcoB Sep 30 '17 at 15:22
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For loops are very ugly in Mathematica and should be avoided whenever possible. @march's solutions are so much more elegant.
But if you're wedded to the idea of using a For loop, here's a very ugly approach to your problem:
mylist = {};
For[i = 1, i < 10, i++, AppendTo[mylist, i^2]]
and then
mylist
answered Sep 29 '17 at 17:49
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For, an even uglier approach but more efficient than usingAppendTois flattening nested lists.mylist = {}; (For[i = 1, i < 10, i++, mylist = {mylist, i^2}]; mylist = mylist // Flatten;)$\endgroup$ – Bob Hanlon Sep 29 '17 at 19:45 -
$\begingroup$ Gosh... perhaps we should start a contest for the ugliest solutions to problems! $\endgroup$ – David G. Stork Sep 29 '17 at 20:27
Table[i^2, {i, 9}].Range[9]^2. See this post.. $\endgroup$ – march Sep 29 '17 at 17:43