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Suppose I have a simple function like $\cos(kx)$, and I am plotting a number of such functions with different values for $k$ as in:

Plot[Table[Cos[k x], {k, 1, 4, 1}], {x, 0, π}]

How can I color them depending on the $k$ parameter without setting it manually myself, as in:

Plot[Evaluate[Table[Cos[k x], {k, 1, 4, 1}]], {x, 0, π},
  PlotStyle -> Table[Blend[{Blue, Red}, k/4], {k, 1, 4, 1}]]

?

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  • $\begingroup$ Plot[Evaluate[Table[Cos[k x], {k, 1, 4, 1}]], {x, 0, \[Pi]}] automatically colors them differently for each k. Is that what you mean? If you want each plot colored specifically but you don't want to specify the colors "manually," then either I don't understand what you want or it cannot be accomplished. $\endgroup$ – Michael E2 Sep 25 '17 at 23:36
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    $\begingroup$ Maybe this?: Plot[Evaluate[Table[Style[Cos[k x], Blend[{Blue, Red}, k/4]], {k, 1, 4, 1}]], {x, 0, \[Pi]}] $\endgroup$ – Michael E2 Sep 25 '17 at 23:38
  • $\begingroup$ @MichaelE2 Yes, that's exactly what I wanted! You got it! I'm gonna study that syntax. $\endgroup$ – Pablo Fernández Esteberena Sep 25 '17 at 23:40
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    $\begingroup$ I was about to suggest Style as @Michael just posted; see (8191) $\endgroup$ – Mr.Wizard Sep 25 '17 at 23:42
  • $\begingroup$ @Michael Do you think this is close enough to 8191 to be marked as a duplicate? $\endgroup$ – Mr.Wizard Sep 25 '17 at 23:51
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This seems to be the desired form:

Plot[
 Evaluate[Table[Style[Cos[k x], Blend[{Blue, Red}, k/4]], {k, 1, 4, 1}]],
 {x, 0, π}]

Mathematica graphics

| improve this answer | |
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It may help to use PlotLabels and PlotLegends options to identify the plotted functions.

Plot[Evaluate[
Table[Style[Cos[k x], Blend[{Blue, Red}, k/4]], {k, 1, 4, 1}]], {x, 0, π}, 
PlotLabels -> Placed[Automatic, {Above, Below, After, Below}], 
PlotLegends -> "Expressions"]
| improve this answer | |
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