4
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This query is similar to a question I posted earlier.

Given

testList = 
  {{"a", "b 3", "cd", "ef 23"}, {"z 12", "y", "x"}, {"z", "y"}, {"a", "b3"}};

I would like to create a rule that would delete 1st level elements of testList that do not contain a string representation of a number. The result would be:

resultList = {{"a", "b 3", "cd", "ef 23"}, {"z 12", "y", "x"}, {"a", "b3"}};
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3 Answers 3

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6
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Although I very much in favor of aardvark2012's answer using Pick, I would like to note that this can done with good old Table.

data = {{"a", "b 3", "cd", "ef 23"}, {"z 12", "y", "x"}, {"z", "y"}, {"a", "b3"}};
Table[If[Or @@ StringContainsQ[item, DigitCharacter], item, Nothing], {item, data}]

{{"a", "b 3", "cd", "ef 23"}, {"z 12", "y", "x"}, {"a", "b3"}}

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8
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One possibility:

Pick[#, Or @@@ StringContainsQ[DigitCharacter] /@ #] &@testList2

or

Select[testList2, Or @@ StringContainsQ[#, DigitCharacter] &]
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2
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If the OP really wants a Rule then anothe options is:

rule = Rule[
  PatternTest[Blank[List],
   Composition[
    Not,
    Apply[Or],
    Map[StringContainsQ[DigitCharacter]]
    ]
   ]
  , Nothing
  ]

Or 

rule= _List?(Not@*Apply[Or]@*Map[StringContainsQ[DigitCharacter]]) -> Nothing

Then

testList /. rule
(* {{"a", "b 3", "cd", "ef 23"}, {"z 12", "y", "x"}, {"a", "b3"}} *)

(testList /. rule) == resultList
(* True *)
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1
  • $\begingroup$ Although admonished not to say thanks, I'll say thanks /@ aardvark2012, m_goldberg,rhermans :) $\endgroup$
    – Suite401
    Sep 24, 2017 at 5:18

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