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I want to determine a list, but I'm finding it difficult:

I need a list with the following characteristic:

ClearAll["Global`*"]
a=1.45;b=a*x;c=b*x;d=1;
list={a,b,c,d}

$\left\{1.45,1.45x,1.45x^2,1\right\}$

What would be the value of x?

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  • $\begingroup$ It is valid for all x. Change the last line to: list[x_] = {a, b, c, d} $\endgroup$ – Bob Hanlon Aug 25 '17 at 14:23
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    $\begingroup$ This appears to be more of a math question than a Mathematica question. $\endgroup$ – Daniel Lichtblau Aug 25 '17 at 14:56
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One option is you use the NestList function:

Last[Solve[1.45x^3==1,{x}]]/.Rule->Set;
NestList[#1x&,1.45,3]

$\{1.45,1.28109,1.13185,1.\}$

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