I have tried as many versions of the following function, but none work.

StringReplace["\[Backslash]" -> ""] /@ {"105\n7.497910", 
 "110\n8.761210", "110\n9.815710"}

1 Answer 1

list = {"105\n7.497910", "110\n8.761210", "110\n9.815710"};

StringReplace[#, "\n" -> "n"] &[list] // FullForm

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  • $\begingroup$ I tried that (at least I think I did) and it didn't work. Thanks for restoring my faith in what I think I know. $\endgroup$ Commented Aug 19, 2017 at 0:08
  • $\begingroup$ Having an "n" on the rhs makes it work. I'm glad to know how to do it. Why can't you use an escape backslash to replace the backslash with ""? $\endgroup$ Commented Aug 19, 2017 at 0:15
  • 1
    $\begingroup$ Because "\n" (newline chatacter) is inseparable. You don't need the "n": StringReplace[#, "\n" -> ""] &[list] also works $\endgroup$
    – eldo
    Commented Aug 19, 2017 at 0:38

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