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I want to plot a vector field in which vectors are unite vectors(I want to show just direction of the vectors). I used vector Plot as below:

u = (x (y^2/(x^2 + y^2))/(x^2 + y^2)^(1/2));
v =  (y (y^2/(x^2 + y^2))/(x^2 + y^2)^(1/2));
VectorPlot[Boole[x^2 + y^2 > 1.5] {u, v}, {x, -5, 5}, {y, -5, 5}]

but it considers the size of vectors. Does anyone know how to solve the problem?

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u = beta (x (-1 + 3 y^2/(x^2 + y^2))/(x^2 + y^2)^(3/2)) /. beta -> 1;
v = (y (-1 + 3 y^2/(x^2 + y^2))/(x^2 + y^2)^(3/2));

VectorPlot[Boole[x^2 + y^2 > 1.5] {u, v}, {x, -5, 5}, {y, -5, 5},
 VectorScale -> {Automatic, Automatic, None},
 ImageSize -> Large]

enter image description here

Different sizes, "but not too much"

VectorPlot[Boole[x^2 + y^2 > 1.5] {u, v}, {x, -5, 5}, {y, -5, 5},
 VectorScale -> {Large, Automatic, Exp[#5] &},
 VectorStyle -> Arrowheads[0.02],
 ImageSize -> Large]

enter image description here

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  • $\begingroup$ is there any way to use different sizes for vectors but the difference is not too much? $\endgroup$
    – OLIVER range
    Aug 4, 2017 at 10:12
  • $\begingroup$ please edit your answer because I have edited the question. So I can chose it as correct $\endgroup$
    – OLIVER range
    Aug 4, 2017 at 10:26
  • $\begingroup$ which parameter controls "too much"? $\endgroup$
    – OLIVER range
    Aug 4, 2017 at 10:49
  • $\begingroup$ Exp[#5]&] - but there are endless possibilities with VectorScale $\endgroup$
    – eldo
    Aug 4, 2017 at 11:01
  • $\begingroup$ to make the difference more clear, should i increase 5? $\endgroup$
    – OLIVER range
    Aug 4, 2017 at 11:08

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