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I would like to use ImageDifference to express the change in motion between 0 and 1.

Dynamic[{data = CurrentImage[2], smart = ImageDifference[data[[1]], data[[2]]]}]

If there is no change, 0, Depending on the degree of change, I want to represent between 0 and 1.

Is there a way to represent the image obtained by ImageDifference between 0 and 1?

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  • $\begingroup$ Probably many ways e.g. you can sum up grayscaled image and normalize with respect to pixel count. But this question is not about Mathematica. $\endgroup$ – Kuba May 18 '17 at 6:31
  • $\begingroup$ Good idea thank you. I wanted to know if there was a Mathematica function that would solve this problem easily. And I found a function called ImageMeasurements. $\endgroup$ – user21427 May 19 '17 at 22:44
  • $\begingroup$ Are you looking for ImageAdjust? $\endgroup$ – Chip Hurst Jul 17 '17 at 15:48
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You can add up the all the pixel values and then divide by the total number of pixels in the image.

Dynamic[data = CurrentImage[2]; 
   {smart = ImageDifference[data[[1]], data[[2]]], 
   {n, m} = ImageDimensions[smart]; 
   Total[Flatten@ImageData[smart]]/(n m)}]
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  • $\begingroup$ Thank you for your kind answers. I used to find a function called ImageMeasurements, and I got results similar to your answer. value = Dynamic@ImageMeasurements[smart, "MeanIntensity"]; $\endgroup$ – user21427 May 19 '17 at 22:42
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    $\begingroup$ @user21427 You should post your solution as self-answer and accept it in order to take this question off the list of unanswered questions. $\endgroup$ – Alexey Popkov Sep 15 '17 at 15:08

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