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The follow line is returning without evaluation:

 InverseFourierTransform[
     CharacteristicFunction[PoissonDistribution[1], t], t, w]

It is meant to output the probability mass function of the Poisson distribution with unit mean.

I can't find the calculation anywhere online. I assume this doesn't evaluate because of the discrete nature of the Poisson distribution? Are there some assumption I need to add?

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  • $\begingroup$ PDF[PoissonDistribution[1], w] does what you want, no? $\endgroup$ – J. M. is away May 10 '17 at 22:14
  • $\begingroup$ Yes that works. So do other inverse Fourier transforms, including the characteristic function of the Gaussian. $\endgroup$ – Alexander Kartun-Giles May 11 '17 at 1:43

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