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My code:

t = Table[a/(1 + Exp[- x]) + 1.72/(1 + Exp[- y]) - 1.1 == 0, {a, -7.0, 7.0, 
0.3}];
ContourPlot[t, {x, -10, 10}, {y, -10, 10} ]

The output is like this:

enter image description here

But I want the curves to be colored in a gradient, like GrayTones or different shades of red, say. Thanks!

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2 Answers 2

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ContourStyle -> Table[GrayLevel[i/47], {i, 0, 46, 1}] ,

where there are 47 values governed by {a, -7.0, 7.0, 0.3}.

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1
  • $\begingroup$ Why 52 and not 50? :) $\endgroup$ Commented May 4, 2017 at 17:29
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I found a solution:

t = Table[a/(1 + Exp[- x]) + 1.72/(1 + Exp[- y]) - 1.1 == 0, {a, -7.0, 7.0, 
0.3}];
t2 = Table[Hue[i], {i, 0, 1.0, 0.015}];
ContourPlot[t, {x, -10, 10}, {y, -10, 10} , ContourStyle -> t2]

The result looks like this:

enter image description here

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