Why is this limit not working?
Limit[I*Sin[alpha^0.5*Betta]*Sin[Lc*Betta*alpha^0.5]/(alpha^0.5*Betta),alpha -> 0]
If I remove the division by alpha it works fine, but it doesn't if I divide the two Sines by alpha
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Sign up to join this communityWhy is this limit not working?
Limit[I*Sin[alpha^0.5*Betta]*Sin[Lc*Betta*alpha^0.5]/(alpha^0.5*Betta),alpha -> 0]
If I remove the division by alpha it works fine, but it doesn't if I divide the two Sines by alpha
Rewriting this way we can reach for some result:
Limit[I*Sin[Sqrt[α]*β]*(Sin[Lc*β*Sqrt[α]]/(Sqrt[α]*β)),α->0]
0
(1/2)
orSqrt
instead of0.5
$\endgroup$ – george2079 Mar 27 '17 at 21:38Betta
. Actually, it is calledBettina
and it looks like this♀
:) $\endgroup$ – halirutan♦ Mar 28 '17 at 4:070.5
? $\endgroup$ – anderstood Mar 28 '17 at 14:44Limit[Sin[x^.5]/x^.5,x->0]
works when you might expect it should not. $\endgroup$ – george2079 Mar 28 '17 at 15:08