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I have a dataset of $ \textbf{B} = {B_x, B_y, B_z}$. (Quite a big dataset :78*100*150)

I want to plot magnetic field lines.

If I was working with an analytical function, the magnetic field line would be defined as

$\frac{dx}{B_x}=\frac{dy}{B_y}=\frac{dz}{B_z}=\frac{ds}{B}$

Where $B=\sqrt{\textbf{B} \cdot \textbf{B}}= B_x^2+B_y^2+B_z^2$. I would then work out an expression for the field by solving the equation, for instance by taking integrals:

$\int B_y dx = \int B_x dy... $

Which would give an expression which evaluates to a constant which I can plot.

For example, I can do this:

bx = y[x]/a;
by = x/a ;
bz = 0;

a = 2
bfield = DSolve[Dt[x]/(bx) == Dt[y[x]]/(by), y[x], x]

Plot[Evaluate[
  y[x] /. bfield /. {C[1] -> Table[x, {x, -10, 10, 2}]}], {x, -7, 7}, 
 PlotRange -> All]

enter image description here Now, I'm not working with an analytical function - I'm working with a datacube. Interpolating it seems like a lot of effort. ListVectorPlot3D doesn't have an option to create field lines. But, how should I plot the magnetic field lines?

Is there anyway I can modify ListVectorPlot3D to have continuous lines which show the strength of the field by how many lines are drawn. Or are there any other functions or good ideas?

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  • $\begingroup$ Unfortunately I think interpolation will be necessary. Then you could use the answers to this question. There are also ListStreamDensityPlot and ListLineIntegralConvolutionPlot, but they work only on 2D slices which is inappropriate if your field lines aren't in a plane. $\endgroup$ – Jens Mar 22 '17 at 3:55
  • $\begingroup$ Is interpolation possible for a vector field? (i.e. with 3 dimensions and a vector at each point). - asked another question to find out - mathematica.stackexchange.com/questions/140778/… $\endgroup$ – Tomi Mar 23 '17 at 10:48
  • $\begingroup$ Yes it is possible, and I posted another answer at the linked question. $\endgroup$ – Jens Mar 23 '17 at 16:53

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