How to make high resolution DiscretizeRegion from the given image?

enter image description here


$\{963, 594\}$

For instance there is a small size (about $10 \times 10$) but high resolution mesh region of Germany

Entity["Country", "Germany"]["Polygon"] /. GeoPosition -> Identity],
Graphics[Disk[{35, 10}, 5]]]

enter image description here

I want to make small size and high resolution mesh region from the given img

Show[img // ImageMesh // DiscretizeRegion, Graphics[Disk[{40, 10}, 5]]]

enter image description here

  • $\begingroup$ could you provide an example image with which to work with? $\endgroup$
    – glS
    Mar 14, 2017 at 11:19
  • $\begingroup$ @glS this is original image, then use ChanVeseBinarize for mask. $\endgroup$
    – vito
    Mar 14, 2017 at 11:43

1 Answer 1


The option DataRange, from the relevant documentation page, does what you want:

Mind that the aspect ratio is not preserved in this way, so you have to manually use the correct values for x- and y-range to preserve the original one.

A way to automatically extract the aspect ratio of the original image is using ImageDimensions:

originalAspectRatio = #[[2]]/#[[1]] &@ImageDimensions@img;
With[{newSize = 40},
   DataRange -> {{0, #}, {0, originalAspectRatio #}} &@newSize],
  Axes -> True, AxesOrigin -> {0, 0}

Wrapping it all up in a function:

meshDiscretizeAndResize[img_Image, newSize_Integer] := With[{
   originalAspectRatio = #[[2]]/#[[1]] &@ImageDimensions@img
    DataRange -> {{0, #}, {0, originalAspectRatio #}} &@newSize

An example showing it work as intended:


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