Suppose I want to plot this function $f(x,y)=x^2-y^2$ and I want to set the domain for $y$ to be $1-y$.

I tried in Mathemtica,

Plot3D[x^2 - y^2, {x, 0, 1}, {1 - y, 0, 1}]

But it gives,

Plot3D::write: Tag Plus in 1-y is Protected.

Any idea, how to handle such situation?


closed as unclear what you're asking by MarcoB, happy fish, Kuba Feb 22 '17 at 6:21

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  • 4
    $\begingroup$ you can substitute z=1-y which is in range [0,1] with y=1-z therefore the corresponding domain for y is [1,0] $\endgroup$ – Rom38 Feb 21 '17 at 5:39
  • 4
    $\begingroup$ Plot3D[x^2 - (1-a)^2, {x, 0, 1}, {a, 0, 1}] like this? I renamed plotting parameter to a = 1- yto not confus ourselves. How else to you want this feature to manifest on the plot? (reversed axis etc) $\endgroup$ – Kuba Feb 21 '17 at 6:47

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