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I'm trying to compute the probability density of a random variable $\log(X)$, where $X \sim \textrm{Gamma}(k, \Theta)$, in Mathematica 11. One way to do this is by:

F[x_] = PDF[TransformedDistribution[Log[X], X \[Distributed] GammaDistribution[k, \[CapitalTheta]]], x]

The answer corresponds to what I can prove by hand:

$$\frac{\Theta ^{-k} e^{k x-\frac{e^x}{\Theta }}}{\Gamma (k)}$$

According to the documentation, "The exp-gamma distribution is mathematically defined to be the distribution that models Y==log(X) whenever X ~ GammaDistribution". Therefore, it seems I should get the same result with

G[x_] = PDF[ExpGammaDistribution[k, \[CapitalTheta], 0], x]

However, the answer is different:

$$\frac{e^{\frac{k x}{\Theta }-e^{x/\Theta }}}{\Theta \Gamma (k)}$$

This is a different function, which can be seen by plotting:

Plot[{F[x], G[x]} /. {k -> 3, \[CapitalTheta] -> 2}, {x, 0, 5}]

What am I missing?

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    $\begingroup$ The relation is shown in Properties & Relations in the documentation for ExpGammaDistribution $\endgroup$ – Simon Woods Feb 15 '17 at 13:49
  • $\begingroup$ @Kaba would you consider expanding your comment into a self-answer? I think it could be beneficial for future reference. $\endgroup$ – MarcoB Feb 16 '17 at 4:43
  • $\begingroup$ @MarcoB I added an answer. $\endgroup$ – kaba Feb 16 '17 at 10:11
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Later in the documentation examples, it is seen that $\mathrm{ExpGamma}[k,\Theta]$ is the distribution of $\Theta \log(X)$, where $X \sim \mathrm{Gamma}[k, 1]$. The $\Theta$ in the $\mathrm{ExpGamma}$ distribution is not related to the $\Theta$ in the $\mathrm{Gamma}$ distribution.

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