# How to find the following integral by numeric?

I don't know how to find the following integral by numeric $$\int_{g(\alpha)}^{h(\alpha)}f(\alpha,x)dx$$ where,say, $f(\alpha ,x)=1-\alpha x+\sqrt{x}\alpha^2$ and $g(\alpha)=2\alpha^2-1$, $h(\alpha)=\sqrt{\alpha}+\alpha$ . I want to calculate the integral above in interval $1/40<\alpha<1/8$ in steps of 0.01 and create a table for computations.

Thanks.

• Have you tried NIntegrate[]? – Feyre Feb 13 '17 at 15:04
• You might consider accepting one of the answers, if one of them answers your question. – Michael E2 May 15 '17 at 10:16

Try this:

f[alpha_, x_] := 1 - x alpha + Sqrt[x] alpha^2;
g[alpha_] := 2 alpha^2 - 1;
h[alpha_] := Sqrt[alpha] + alpha;
Table[NIntegrate[f[alpha, x], {x, g[alpha], h[alpha]}], {alpha, 1/40.,1/8.,0.01}]

f[a_, x_] = 1 - a x + Sqrt[x] a^2;

g[a_] = 2 a^2 - 1;

h[a_] = Sqrt[a] + a;

int[a_] =
Assuming[{1/40 < a < 1/8}, Integrate[f[a, x], {x, g[a], h[a]}]]

(*  1 + Sqrt[a] + (3*a)/2 - (5*a^2)/2 -
a^(5/2) - (5*a^3)/2 + 2*a^5 +
(2/3)*a^2*(a*Sqrt[Sqrt[a] + a] +
I*(1 - 2*a^2)^(3/2) +
Sqrt[a^(3/2) + a^2])  *)

Plot[Evaluate@ReIm[int[a]], {a, 1/40, 1/8},
PlotLegends -> {Re, Im},
AxesLabel -> {a, None},
Epilog -> Inset[
LogPlot[
Evaluate@ReIm[int[a]], {a, 1/40, 1/8},
PlotLabel -> "LogPlot"],
{0.09, 2/3}]] Table[{a, int[a]}, {a, 1/40., 1/8., 0.01}] // Grid • i've said that the $\alpha$ values are discrete and obtain a numerical integration then each computations of $\alpha$ is inserted into a table. – Ali184 Feb 14 '17 at 5:43
• very thanks for your complete answer. – Ali184 Feb 14 '17 at 7:07

If it is possible to get a closed form for the integral that is preferable as it simplifies the downstream processing. Note: this is not always possible.

Integrate[f[alpha, x], {x, g[alpha], h[alpha]},
Assumptions -> 1/40 <= alpha <= 1/8]

(* 1 + Sqrt[alpha] + (3 alpha)/2 - (5 alpha^2)/2 - alpha^(
5/2) - (5 alpha^3)/2 + 2 alpha^5 +
2/3 alpha^2 (alpha Sqrt[Sqrt[alpha] + alpha] +
I (1 - 2 alpha^2)^(3/2) + Sqrt[alpha^(3/2) + alpha^2]) *)


Now define a function, f2

f2[alpha_] :=
1 + Sqrt[alpha] + (3 alpha)/2 - (5 alpha^2)/2 - alpha^(5/2) - (
5 alpha^3)/2 + 2 alpha^5 +
2/3 alpha^2 (alpha Sqrt[Sqrt[alpha] + alpha] +
I (1 - 2 alpha^2)^(3/2) + Sqrt[alpha^(3/2) + alpha^2])


To generate the table

Table[{alpha, N@f2[alpha]}, {alpha, 1/40, 1/8, 1/40}]

(* {{1/40, 1.19395 + 0.000415886 I}, {1/20,
1.29172 + 0.00165418 I}, {3/40, 1.37048 + 0.0036869 I}, {1/10,
1.43738 + 0.00646767 I}, {1/8, 1.49509 + 0.00993222 I}} *)