-3
$\begingroup$

How do i find the inverse laplace transform of following function:

f[s]=Exp[(1-s)(1+1/s)]

Mathematica returns exactly the simplified function without computing it.

$\endgroup$

closed as off-topic by MarcoB, corey979, Feyre, Young, m_goldberg Feb 11 '17 at 23:40

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – MarcoB, corey979, Feyre, Young, m_goldberg
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ What is this 3 in title? $\endgroup$ – zhk Feb 11 '17 at 19:34
  • 1
    $\begingroup$ @MMM Maybe to distinguish it from 50862 and 102042? $\endgroup$ – QuantumDot Feb 11 '17 at 19:41
  • $\begingroup$ @QuantumDot You are absolutely right! $\endgroup$ – zhk Feb 11 '17 at 19:43
3
$\begingroup$

It works just fine

InverseLaplaceTransform[(1 - s) (1 + 1/s), s, x]

1-δ′(x)

LaplaceTransform[%, x, s]

1/s - s

$\endgroup$
  • $\begingroup$ Sorry the right function is above $\endgroup$ – PhysicsExams Feb 11 '17 at 21:52

Not the answer you're looking for? Browse other questions tagged or ask your own question.