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I have two functions which depend on the same parameters and I want to make a manipulate box with both of them, but I want to use one slider to control both function (so I can compare how change in a parameter affects both of them).

The easiest way would be to use Plot command with both of them inside, but they have different y axis so I cannot use it.

For now I use Panel and I have two graphs next to each other, but they have separate sliders with the same parameters.

What is the way out of this?

EXAMPLE

Panel[Manipulate[
   Plot[-9.81*t, {t, 0, Sqrt[2*h/9.81]}, PlotStyle -> Red ], {h , 1, 
    100}] Manipulate[
   Plot[h - 9.81*t^2/2, {t, 0, Sqrt[2*h/9.81]}], {h, 1, 100}] , 
 FrameMargins -> 0]
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    $\begingroup$ Could you add code examples. Its much easier to understand what you are talking about, and its much more likely that somebody would help you if you place code examples (properly formatted) that can be copied easily into Mathematica session. $\endgroup$
    – ercegovac
    Feb 3, 2017 at 16:08
  • $\begingroup$ @ercegovac thanks for the tip! Added a simple example, as you suggested $\endgroup$ Feb 3, 2017 at 16:17
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    $\begingroup$ Manipulate[Row@{ Plot[a, {x, 0, 1}, PlotRange -> {0, 10}, ImageSize -> Large], Plot[2 a, {x, 0, 10}, PlotRange -> {0, 10}, ImageSize -> Large] }, {a, 0, 5} ] $\endgroup$
    – grbl
    Feb 3, 2017 at 16:18
  • $\begingroup$ Thanks @grbl. What is the "@" sign for? Is it part of Row function? $\endgroup$ Feb 3, 2017 at 16:24
  • $\begingroup$ @lough_or_cry , you should really familiarize yourself with Mathematica and its paradigm (functional programming). In this particular case @ stands for Prefix operator (search Mathematica help, its powerful ). I'd recommend the following link it gives some useful tips and tricks to jump-start with Mathematica. $\endgroup$
    – ercegovac
    Feb 3, 2017 at 16:27

2 Answers 2

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Full example of my comment:

Manipulate[
   Column@{Plot[-9.81*t, {t, 0, Sqrt[2*h/9.81]}, PlotStyle -> Red, 
    Frame -> True, 
    ImagePadding -> {{30, 10}, {30, 10}}],
   Plot[h - 9.81*t^2/2, {t, 0, Sqrt[2*h/9.81]}, Frame -> True, 
     ImagePadding -> {{30, 10}, {30, 10}}]},
   {h,1, 100}]
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  • $\begingroup$ I have problems with adjusting the spacing between the graphs: usually I would use Column[{},Spacings -> s], but it doesn't seem to work $\endgroup$ Feb 4, 2017 at 10:38
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This seems to work too for your particular example.

Manipulate[Show[Plot[-9.81*t, {t, 0, Sqrt[2*h/9.81]}, PlotStyle -> Red, 
Frame -> True, ImagePadding -> {{30, 10}, {30, 10}}, PlotRange -> All], 
Plot[h - 9.81*t^2/2, {t, 0, Sqrt[2*h/9.81]}, Frame -> True, 
ImagePadding -> {{30, 10}, {30, 10}}, PlotRange -> All]], {h, 1,100}]

enter image description here

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