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I want a phase diagram that characterizes the path of p and s using 

StreamPlot[
 {p^1.3 - .036*s, 0.05*p - 1500000000000/s},
 {s, 10^8, 2*10^8},
 {p, 100000, 200000}, 
 PlotRange -> {{10^8, 2*10^8}, {100000, 200000}}
]

The Output

But that is not right. I'm expecting more paths.

Any suggestions on how to get more paths?

(I know, I have some big numbers, but if it provides one path, why not others? I'd rather not re-scale if I can get it to work this way because the quantities are meaningful.)

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2
  • $\begingroup$ StreamPlot does not do well with poorly scaled domains, in my experience. In rescaling, you can use Ticks to get the ticks marked as you like. $\endgroup$
    – Michael E2
    Jan 24, 2017 at 21:57
  • $\begingroup$ Try @Rahul's myStreamPlot from this answer to improve the spacing $\endgroup$
    – Chris K
    Jan 25, 2017 at 2:16

1 Answer 1

Reset to default
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Like this?

StreamPlot[{(p^1.3 - .036*s)/1000, .05*p - 1500000000000/s} /. s -> 1000 s // Evaluate,
 {s, 10^5, 2*10^5}, {p, 100000, 200000},
 PlotRange -> {{10^5, 2*10^5}, {100000, 200000}}, 
 FrameTicks -> {{Automatic, Automatic},
   {Charting`ScaledTicks[{#/1000 &, 1000 # &}], 
    Charting`ScaledFrameTicks[{#/1000 &, 1000 # &}]}}]

Mathematica graphics

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2
  • $\begingroup$ My goodness that's beautiful! FYI, that is the phase diagram of the total U.S. housing market where the horizontal axis is the average housing unit price and the other axis is housing supply. A change in the cost of ownership, e.g. will leave the system off the saddle point static equilibrium. $\endgroup$
    – Scott
    Jan 25, 2017 at 19:22
  • $\begingroup$ There's a problem with the solution provided by Michael E2. The axis seemed to be reversed, or, is it possible that they have been rescaled incorrectly? $\endgroup$
    – Scott
    Jan 26, 2017 at 1:44

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