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I'd like to compute the derivative (Jacobian) of the function $\mathbf{\Psi\left(\mathbf{F}\right)}$ w.r.t. $\mathbf{F}$ where $\mathbf{F}$ is a 2x2 matrix and $G$ and $v$ are just real constants;

$$ \begin{align} \Psi(\mathbf{F}) &= \frac{\mu}{2} \left( \text{tr}\left(\mathbf{F}^\top \mathbf{F}\right)-2\right)- \mu\log(\text{det}\left(\mathbf{F}\right)) + \frac{\lambda} {2}\log^2\left({\text{det}\left(\mathbf{F}\right)}\right)\\ \mu &= \frac{G}{2\left(1+v\right)}\\ \lambda &= \frac{Gv}{(1+v)(1-2v)}\\\\ G, v &\in {\rm I\!R}\\ \mathbf{F} &\in {\rm I\!R}^{2\times2}\\\\ \frac{\partial\mathbf{\Psi}}{\partial\mathbf{F}} &= \text{?} \end{align} $$

I've come up with the following formula for MMA, but I'm not sure if it produces the correct result;

F = Array[a, {2, 2}]

D[
   G/(2*(1 + v))             * (Tr[Transpose[F]*F] - 2) - 
   G/(2*(1 + v))             * Log[Det[F]] + 
   G*v/(2*(1 + v)*(1 - 2*v)) * Log[Det[F]]^2,
{F}] // MatrixForm // Simplify

Is there any mistake in the code? And even if there'd be no mistake, can I get a better-formatted result (maybe using matrix operations, instead of explicit usage of the matrix's elements, when possible)? (Please bear in mind I'm absolute beginner with Mathematica.)

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