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I have six tables of data say

t1 = {{1, 4}, {2, 2}, {3, 3}};
t2 = {{1, 3}, {2, 5}, {3, 5}};
t3 = {{1, 2}, {2, 7}, {3, 4}};
t4 = {{1, 5}, {2, 8}, {3, 9}};
t5 = {{1, 8}, {2, 1}, {3, 8}};
t6 = {{1, 9}, {2, 5}, {3, 3}};

I want to add all data such that first data in the brace remains same but the second data are added up.

For an example:

tsum1 = {{1,31},{2,34},{3,32}};

How can I do it in Mathematica? Thanks in advance.

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  • $\begingroup$ how did you get {{1,31},{2,34},{3,32}}? I get {{1, 31}, {2, 28}, {3, 32}} $\endgroup$ – Nasser Jan 11 '17 at 4:03
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Add the tables and then divide the numbers in the first column by the number of lists you added:

MapAt[#/6 &, t1 + t2 + t3 + t4 + t5 + t6, {{All, 1}}]
(* {{1, 31}, {2, 28}, {3, 32}} *)

#/6 & is a function that returns the argument divided by 6, and this function is applied to the first column.

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Basically operationally equivalent to kglr's second option, but sans Transpose:

With[{d = {t1, t2, t3, t4, t5, t6}},
 Thread@{First /@ First@d, Last /@ # & /@ d // Total}
 ]
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Some approaches:

  • for this specific example

    {#1/6, #2} & @@@ (t1 + t2 + t3 + t4 + t5 + t6)
    
  • using Sow and Reap:

    ts = {t1, t2, t3, t4, t5, t6}
    Reap[Sow[#2, #1] & @@@ Join @@ (ts), _, {#1, Total@#2} &][[-1]]
    
  • using Association and Merge:

    ds =Rule @@@ # & /@ ts;
    List @@@ Normal[Merge[ds, Total]]
    
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t = {t1, t2, t3, t4, t5, t6}
asc = Association /@ (Rule @@@ # &/@ t)

List@@@Normal@Merge[Total][asc]

{{1, 31}, {2, 28}, {3, 32}}

or

Transpose@{t[[1, All, 1]], Total@t[[All, All, 2]]}

{{1, 31}, {2, 28}, {3, 32}}

or

♯0 = {#/6, #2} & @@@ +## & @@ # &;
♯0 @ t

{{1, 31}, {2, 28}, {3, 32}}

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May be a little bit hacky, but this seems to work

data = ToExpression["t" <> ToString[#]] & /@ Range[6];
{data[[1, #, 1]], Total[data[[All, #, 2]]]} & /@ Range[3]

Mathematica graphics

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  • $\begingroup$ Ah... that can work. $\endgroup$ – David G. Stork Jan 11 '17 at 4:07

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