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It is a elemental question maybe,but I am confusing still.If I have a 1-dimension list list

a = Range[5]
(* {1, 2, 3, 4, 5} *)

So I can do this to get the first and last element:

a[[{1, -1}]]
(* {1, 5} *)

But when I have a matrix mat,why I cannot do this with same method?

mat = Partition[Range[12], 4];
mat[[{{1, 1}, {-1, -1}}]]

This expression will put some error information.

Question

  1. Did I make any grammatical mistakes?
  2. Can we use any elegant method to get this two elements?
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  • $\begingroup$ You can use Extract with similar syntax, I believe. $\endgroup$
    – march
    Dec 27, 2016 at 4:25
  • $\begingroup$ You can use mat[[1,1]] and mat[[-1,-1]]. Or to use same syntax as 1D example, can Flatten the matrix first. $\endgroup$
    – Nasser
    Dec 27, 2016 at 4:28
  • $\begingroup$ @march Good point out,just little pitty,we cannot asign it by same syntax Extract[mat,{{1,1},{-1,-1}}]={c,d}.This is my purpose actually. $\endgroup$
    – yode
    Dec 27, 2016 at 4:28
  • $\begingroup$ @Nasser Thanks advice,which is a good suggestion. $\endgroup$
    – yode
    Dec 27, 2016 at 4:31
  • $\begingroup$ I find using [[x,y]] much easier and more common with other languages (Matlab, etc...) than having to call functions to do it $\endgroup$
    – Nasser
    Dec 27, 2016 at 4:31

1 Answer 1

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Does the following help:

mat = Partition[Range[12], 4];
{#[[1, 1]], #[[-1, -1]]} & @ mat

Or, alternatively,

{First@First@#, Last@Last@#} & @ mat
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  • $\begingroup$ suspect you are looking for something different than the following. mat[[1, 1]] = a; mat[[-1, -1]] = b; mat // TableForm $\endgroup$
    – user6546
    Dec 27, 2016 at 4:42
  • $\begingroup$ @Thanks, :)If we just extract,we can use {First@#, Last@#} &@Flatten[mat] or Through[{First,Last}[Flatten[mat]]] $\endgroup$
    – yode
    Dec 27, 2016 at 5:14

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