I am trying to model a tank with discontinuous flow into the tank and discontinuous flow out of the tank. I do it numerically. You can imagine a tank to which I feed blue balls at timepoint t0, red balls at timepoint t1 and so on. I assume instantaneous mixing of the solutions in the tank. When I take out part of the solution in the tank, I will remove same proportions of the different colored balls. After some time, I will have removed more blue balls (i.e. balls that have been longer in the tank) than balls of a color that I added to a later point. I want to calculate the residence time distribution of let's say the blue balls over time.

I post here the first iteration steps to give you an idea. My problem is that I don't manage to program the iteration. I tried to use an approach with Do and Reap/Sow to get the results of each individual iteration, but I didn't manage to solve it.

I have two example lists needed for the problem (of same length): My real lists are much longer.

timeVolIn={{0,5},{1,5},{2,2},{3,1},{4,2}}(*this as the form of a nested list with {time,volIn}*)
volOut={1,5,3,2}(*volOut at each time*)

the first iteration:

result1=If[volOutFactor==0,#*{1,1},#*{1,volOutFactor}]/@input1 (*the "If" is necessary because my volOut[[i]] can be zero. In this case I don't want anything to happen, therefore the *{1,1}*)

the second iteration:


the third iteration:


I think you get the kind of iteration I need from that. I want to collect all results. This would call for NestList, but I can't manage it. The output has to be a nested list in which each the first sublist (=result of the first iteration) is of length 2, the second sublist (=result of the second itereation is of length 3) and so on.

Thanks in advance!!

  • 2
    $\begingroup$ You would probably want to start by re-writing your iteration steps into a single function that you can apply to some starting value. You might also be interested in Fold / FoldList for this purpose if you have to pass a second argument to your iteration function, in addition to the result of the previous iteration. $\endgroup$ – MarcoB Nov 10 '16 at 17:55
  • $\begingroup$ My problem with FoldList (or NestList) is that I don't know how to set up the first iteration. The first iteration has to be timeVolIn[[1;;2]], but in the second iteration onwards it is the OUTPUT of the last iteration. $\endgroup$ – Niki Nov 11 '16 at 6:32
  • $\begingroup$ Niki, perhaps you might want to take another look at the NestList documentation. NestList in fact does exactly what you describe. For instance: NestList[function, startingValue, numberOfIterations] will return a list containing the starting value first, and then the results of repeatedly applying function to it. Perhaps you might want to look at the results of NestList[2#&, 3, 4]: this applies a doubling function four times, starting on the value 3, to give {3, 6, 12, 24, 48}. Is this not along the lines of what you need? $\endgroup$ – MarcoB Nov 11 '16 at 15:15
  • $\begingroup$ I tried the following, but no success: i = 2; NestList[j = i++; If[volOut[[j]] == 0, #*{1, 1}, #*{1, (volOut[[j]]/(#[[All, 2]] // Total))}] & /@ input1 &, timeVolIn[[1 ;; 2]], (timeVolIn // Length - 1)] ... My problem is that the "input1" should be the result from the last iteration. So how can is use the "Map" inside the "NestList. I have just too many #, so I get lost. $\endgroup$ – Niki Nov 11 '16 at 15:30

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