# Laurent series 0 < |z-3| < 3

I wanna check my laurent series exercises on Mathematica, but can't seem to find a command or program to achieve the result of such type of interval.

$f(z)=\frac{1}{(z-3) z},\\1<|z-3|<3$

The command Series[] won't let me use $z-3$ as the expansion variable.

Series[1/(z - 3)/z, {z, 3, n}]

Just change n to be the number of terms you want in the expansion.
• You can use SeriesCoefficient too and not need to replace n with an explicit integer. – Chip Hurst Oct 18 '16 at 17:45