The Hodge dual of a $p$-form is explicitly metric dependent, but the function
HodgeDual doesn't seem to ask for the metric as an argument. How does that work? Does it mean that
HodgeDual can only do the computation in Euclidean space?
Mathematica Stack Exchange is a question and answer site for users of Wolfram Mathematica. It only takes a minute to sign up.Sign up to join this community