# How does HodgeDual work?

The Hodge dual of a $p$-form is explicitly metric dependent, but the function HodgeDual[] doesn't seem to ask for the metric as an argument. How does that work? Does it mean that HodgeDual[] can only do the computation in Euclidean space?

• Yes, currently HodgeDual assumes the metric is Euclidean. – jose Oct 10 '16 at 18:13