# Solving a nonlinear recurrence equation

How to solve the following nonlinear recurrence equation using RSolve?

$$a(n+1):=\frac{1-(1-a(n)^4)^{1/4}}{1+(1-a(n)^4)^{1/4}} , \quad a(0):=\sqrt{2}-1$$

I tried:

RSolve[{a[n + 1] == (1 - (1 - a[n]^4)^(1/4))/(1 + (1 - a[n]^4)^(1/4)),
a[0] == Sqrt[2] - 1}, a[n], n]


Then I tried Wolfram Alpha, but $a(3)$ and $a(4)$ equal zero!

WolframAlpha["a[n + 1] =(1 - (1 - a[n]^4)^(1/4))/(1 + (1 - \
a[n]^4)^(1/4)), a(0)=Sqrt(2)-1", {{"Values", 1}, "Content"}]


• What makes you think there should be a closed-form solution? – masterxilo Oct 4 '16 at 21:40

 a[0] := N[Sqrt[2] - 1]

• $a(n)=0$ for $n\geq3$, I tried a[0] := N[Sqrt[2] - 1, 200] but nothing change – vito Oct 4 '16 at 11:33
• you can start with symbolic a[0] then N[a[3],20] yields ~10^-44, a[4] ~ 10^-175 is there a point to this? – george2079 Oct 4 '16 at 14:09