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I have an $N\times 2$ matrix $A = \begin{pmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \\ \vdots & \vdots \\ a_{N1} & a_{N2} \end{pmatrix}$. What is the cleanest code to make a new $N\times 2$ matrix $B$ with the first column unchanged but second column should consist of elements of second column of $A$ divided by the corresponding element of the first column of $A$. That is $a_{1i}$ divide by $a_{i1}$.

Thus the elements of $B$ should read

$B=\begin{pmatrix} a_{11} & a_{12}/a_{11} \\ a_{21} & a_{22}/a_{21} \\ \vdots & \vdots \\ a_{N1} & a_{N2}/a_{N1} \end{pmatrix}$

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    $\begingroup$ What about b = {#1, #2/#1} & @@@ a, clean enough? $\endgroup$ – BlacKow Sep 30 '16 at 15:32
  • $\begingroup$ Woah. That's an answer. $\endgroup$ – Your Majesty Sep 30 '16 at 15:35
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(*matlab-like approach*)

nRows = 5;
nCols = 2;
(mat = Table[i + j, {i, nRows}, {j, nCols}]) // MatrixForm

Mathematica graphics

mat[[All, 2]] = mat[[All, 2]]/mat[[All, 1]];
mat // MatrixForm

Mathematica graphics

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  • $\begingroup$ +1 Also: mat[[All, 2]] /= mat[[All, 1]] $\endgroup$ – WReach Sep 30 '16 at 18:40
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It's always nice to have a clean method, but if you have large matrix, performance can be an issue. Consider following comparison:

a = RandomReal[1, {1000000, 2}];
{t1, r1} = AbsoluteTiming[{#1, #2/#1} & @@@ a];
{t2, r2} = AbsoluteTiming[Transpose@{#1, #2/#1} & @@ Transpose@a];
{t1, t2, r1 == r2} 
(* {1.48458, 0.024882, True} *)

The first solution iterates over large index, it makes it way slower, although a little bit more cleaner visually.

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  • $\begingroup$ Good demonstration! $\endgroup$ – Your Majesty Sep 30 '16 at 16:19

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