# List positions without brackets [duplicate]

Suppose I have a list l which contains the indices of some array a. For instance,

l = {{1,1},{1,2}}
a = {{a11,a12},{a21,a22}}


I want to access the elements of a at the positions given by l, i.e. in this case I want to access

a[[1,1]] = a11
a[[1,2]] = a12


However, I cannot simply feed the elements of l into the a with double brackets:

In[1]:= a[[{1, 1}]]
Out[2]= {{a11, a12}, {a11, a12}}


Is there an easy way to remove the curly brackets in the entry of the list? It should be generalizable to much bigger arrays (so not something like a[[l[[1,1]],l[[1,2]]]] = a11).

## marked as duplicate by Kuba♦ list-manipulation StackExchange.ready(function() { if (StackExchange.options.isMobile) return; $('.dupe-hammer-message-hover:not(.hover-bound)').each(function() { var$hover = $(this).addClass('hover-bound'),$msg = $hover.siblings('.dupe-hammer-message');$hover.hover( function() { $hover.showInfoMessage('', { messageElement:$msg.clone().show(), transient: false, position: { my: 'bottom left', at: 'top center', offsetTop: -7 }, dismissable: false, relativeToBody: true }); }, function() { StackExchange.helpers.removeMessages(); } ); }); }); Sep 20 '16 at 14:27

I think Sequence does the job for you:
a[[Sequence @@ l[[1]]]]

Equivalently, without (most) brackets, call it Part:
Part[a, Sequence @@ l[[1]]]