Is there a way to create a two-way association or a bijection between two lists of equal length? I know I can use AssociationThread twice, flipping the arguments, but how can I create a bijective function which associates each element in one list with an element of another, and vice-versa?
$\begingroup$
$\endgroup$
2
-
$\begingroup$ In what way does the solution you mention fall short of what you want? $\endgroup$– AlanSep 13, 2016 at 3:21
-
$\begingroup$ @Alan its more clunky: using two variables instead of one. $\endgroup$– Matt GSep 13, 2016 at 3:24
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
A bijective function:
list1 = {1, 2, 3, 4};
list2 = {5, 6, 7, 8};
MapThread[(f[#] = #2; f[#2] = #) &, {list1, list2}]
f[2]
(* Out: 6 *)
And the AssociationThread solution that you mention:
f = <|AssociationThread[list1 -> list2], AssociationThread[list2 -> list1]|>;
f[2]
(* Out: 6 *)
