4
$\begingroup$

I tried to fit my data to a log-normal distribution, but I didn't get a correct result. Can anyone help to find out how to do this?

x = {500, 510, 520, 530, 540, 550, 560, 570, 580, 590, 600};
y = {3891.13897, 6447.2735, 6379.05724, 4781.9429, 3236.44741, 
2283.12663, 1.81827, 1132.17598, 733.89458, 487.24879, 321.50395};
Improve this question
$\endgroup$
6
  • 1
    $\begingroup$ I suggest posting the data in a more friendly form first. Preferably in a column format and using the code tags. $\endgroup$ – Q.P. Sep 11 '16 at 17:03
  • $\begingroup$ I hope now its fine. Thank you for your suggestion. $\endgroup$ – Anita Maheshwari Sep 11 '16 at 17:13
  • $\begingroup$ You can format inline code and code blocks by selecting the code and clicking the {} button above the edit window. The edit window help button ? is also useful for learning how to format your questions and answers. You may also find this meta Q&A helpful -- The idea is to make it so that others can copy-paste it into the software Mathematica. It makes it convenient for them and more likely you will get someone to help you. You will need to put the data in proper Mathematica syntax. $\endgroup$ – Michael E2 Sep 11 '16 at 17:26
  • 1
    $\begingroup$ The y-values aren't counts or relative frequencies so why would you want to fit a probability distribution? Do you want to fit a curve that happens to have the same shape as a lognormal probability density function? $\endgroup$ – JimB Sep 11 '16 at 17:35
  • $\begingroup$ And is the value 1.81827 correct? $\endgroup$ – JimB Sep 11 '16 at 17:37
4
$\begingroup$

I assume that the y variable 1.81827 is a typo that should be 1818.27.

The common practice in fittin a log-normal distribution is to fit a normal distribution to a set of logarithmic data:

data = Transpose@{Log10@x, y};

I use the NonlinearModelFit:

nlm = NonlinearModelFit[data, a + b Exp[-(μ - z)^2/(2 σ^2)], {a, b, μ, σ}, z];
Normal@nlm

731.951 + 5607.06 E^(-2055.8 (2.71362 - z)^2)

To plot the data and the fit:

pts = ListPlot[data, Frame -> True];
plot = Plot[Normal[nlm], {z, Min@Log10@x, Max@Log10@x}, Frame -> True];
out = Show[pts, plot, Frame -> True, FrameLabel -> {"log10x", Rotate["y", 270 Degree]}, Frame -> True]

enter image description here

The parameters and uncertainties of the fit can be obtained via

table1 = nlm["ParameterTable"]

enter image description here

or with another useful command:

param = nlm["BestFitParameters"]

{a -> 731.951, b -> 5607.06, [Mu] -> 2.71362, [Sigma] -> 0.0155953}

which allow, e.g., to get the location of the mean in the initial units:

10^(μ /. param)

517.156

The mean, standard deviation and variance of the log-normal distribution may be obtained with the formulae displayed, e.g., on wikipedia.

Improve this answer
$\endgroup$
3
  • $\begingroup$ You've fit a curve to the data that has the same shape as a lognormal distribution. But that in no way imparts properties such as mean, variance, etc. $\endgroup$ – JimB Sep 11 '16 at 18:54
  • $\begingroup$ Well, I'm sure of my approach as it is my field of scientific expertise for some time now. Another thing is whether this data really comes from a log-normal distribution - data that I work with span >6 orders of magnitude, so it's quite obvious in that case. The x here, on the other hand, are not very broad so log-normal may not be the right choice. However, this was the OP's request to fit such a distribution. $\endgroup$ – corey979 Sep 11 '16 at 19:10
  • $\begingroup$ My comment was very specific to the inferring of any probabilistic characteristics such as mean, variance, cumulative distribution function, probability density function, etc., from the fitted curve. One can't make such inferences as you imply in your last sentence from the data associated with this question. $\endgroup$ – JimB Sep 11 '16 at 20:23

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.