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How do I use mathematica to simplify an exponent by breaking it up into its constituents and setting one of them equal to a constant?

For instance,

E^(k - 1/x)

would become

E^(k) * E^(1/x)

which I could then simplify to a using

 /.E^(k)->a
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  • $\begingroup$ Look here $\endgroup$ – corey979 Sep 5 '16 at 20:21
  • $\begingroup$ You could do: E^(k - 1/x) /. k -> Log[a] $\endgroup$ – JungHwan Min Sep 5 '16 at 20:22

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