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How do I make a graph of a function which takes a date as input, over a full year?

[Edit] To clarify, I have an existing function, say f, which takes a date as input and returns a value between 0 and 90. I want to plot this function over the year 2016, so plot the value for every day in 2016.

My try

I can reduce this question to making a list like 

Table[
 {d, f[d]},
 {d, DateObject[{2016, 1, 1}], DateObject[{2016, 12, 31}]}
 ]

and then doing ListPlot or something, but obviously I need to give Mathematica at least the step size (one day) and find a way to add a day to a date in such an iteration.

Maybe DateRange is an idea to make a list of dates of a year, but not sure how I would attach my function to that properly.

PS I'm on Mathematica 11.0

[Edit] As per request, my own function is a little big too put here, but for example function

g[d_] := (
  DateValue[d, "Month"] + DateValue[d, "Day"]
  )

Will do, I guess.

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  • $\begingroup$ what do you want your graph to look like? $\endgroup$ – Conor Cosnett Aug 20 '16 at 16:22
  • $\begingroup$ I'm guessing you want date on x axis? what do you want on y axis? $\endgroup$ – Conor Cosnett Aug 20 '16 at 16:23
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    $\begingroup$ @ConorCosnett (sorry for the delay) No sorry I think you misinterpreted the question, I'm asking how to make a graph of a function which takes a date as input, I already have a (big) function which works fine, it returns a value between 0 and 90 given a date. I'll try to clarify the question, hope it helps $\endgroup$ – PHPirate Aug 20 '16 at 17:06
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    $\begingroup$ @ConorCosnett Edited question for example function $\endgroup$ – PHPirate Aug 20 '16 at 17:21
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    $\begingroup$ I fixed my function now @PHPirate $\endgroup$ – Conor Cosnett Aug 20 '16 at 17:21
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solution with DateListPlot

Clear[f,g]
f = Function[x, DateObject[{2016, 1, 1}] + Quantity[(x-1), "Days"]]
g[d_] := (DateValue[d, "Month"] + DateValue[d, "Day"])
listOfDates = Table[{f[d], g[f[d]]}, {d, 1, 365}];

DateListPlot[listOfDates]

enter image description here

ListPlot[Table[g[f[d]], {d, 1, 365}]]

enter image description here

Here is a function which you give 1 to return the first day 1 in 2016 ect.

use Quantity 

f = Function[x, DateObject[{2016, 1, 1}] + Quantity[(x-1), "Days"]]

Table[{f[d], g[f[d]]}, {d, 1, 365}]

enter image description here

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  • $\begingroup$ For me, the addition of dates doesn't work... I get back for f[3] the date plus days, so 3 + DateObject[{2015, 12, 31}] (Oh, I'm on MMa 11, if that is relevant) $\endgroup$ – PHPirate Aug 20 '16 at 16:29
  • $\begingroup$ @PHPirate Could you describe the output of your function? $\endgroup$ – Conor Cosnett Aug 20 '16 at 16:44
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    $\begingroup$ Oh I just saw it, yes that works, but is there a possibility to put some real dates on the x-axis instead of day of year? Just for the fancy looks... Maybe the month? $\endgroup$ – PHPirate Aug 20 '16 at 17:29
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    $\begingroup$ Just googled for that, I think it should be fixed with using DateListPlot? Anyway, +1 for helping me learn that adding a number to a date doesn't work, but adding a quantity does! $\endgroup$ – PHPirate Aug 20 '16 at 17:32
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    $\begingroup$ @PHPirate I included DateListPlot now $\endgroup$ – Conor Cosnett Aug 20 '16 at 17:44

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