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We know that the KroneckerProduct of two matrices a and b will be done as

a = {{2, 1}, {I, 3}}; b = {{2, 3, 1}, {1, 4, 6}, {2, 4, 6}};
m=KroneckerProduct[a,b]
(**{{4, 6, 2, 2, 3, 1}, {2, 8, 12, 1, 4, 6}, {4, 8, 12, 2, 4, 6}, {2 I, 
3 I, I, 6, 9, 3}, {I, 4 I, 6 I, 3, 12, 18}, {2 I, 4 I, 6 I, 6, 12, 
18}}**

Is there any defined reverse procedure by which if we have a given matrix such as m we be able to access a and b?!

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  • $\begingroup$ The certainly won't be a unique solution. It is ambiguous at least to a multiplicative factor. $\endgroup$
    – mikado
    Jul 29 '16 at 10:55
  • $\begingroup$ @ J. M. thank you so much for your suggested address, I must read that carefully to understand what happened. $\endgroup$ Jul 29 '16 at 11:08

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