If you use Mathematica to do this integral:

Integrate[1/(x^2 - a^2), x]

you will get a uncommon function form like


Well, I don't like ArcTanh. And as we know the result should be $$\frac{1}{2a}\log\left|\frac{x-a}{x+a}\right|$$It's equal to the Mathematica result. But can I change the result of Mathematica into this form?


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