0
$\begingroup$

If you use Mathematica to do this integral:

Integrate[1/(x^2 - a^2), x]

you will get a uncommon function form like

-(ArcTanh[x/a]/a)

Well, I don't like ArcTanh. And as we know the result should be $$\frac{1}{2a}\log\left|\frac{x-a}{x+a}\right|$$It's equal to the Mathematica result. But can I change the result of Mathematica into this form?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.