Good day,

First of all, sorry if my coding in this forum has mistake. I already learned it and this is the best try from me.

May anyone help me troubleshoot my problem below.

β1 = 0; 
β3 = Pi; 
β2 = Pi/2;
For[t = 0, t < 10, t++,
    A={{E^(I β1 + I β3) Cos[t*β2],   E^(I β1 - I β3) Sin[t*β2]},
  {(-E^((-I) β1 + I β3)) Sin[t*β2], E^((-I) β1 - I β3) Cos[t*β2]}}; 
   Print[A];Print[t];t = t + TimeUsed[]]

I get the output as example as below,















suppose the answer will include the symbol I. But what the mistake that I did.?

Thank you

Thank you for the @Edmund according to Euler Formula. I already read that and it correct output from the coding.

Since the Euler Formula is given by,

e^(ix)= Cosx+ iSinx. 

where the x in angle rotating the plane.

Thank you


closed as off-topic by MarcoB, george2079, Yves Klett, bbgodfrey, Sumit Jul 25 '16 at 14:54

  • The question does not concern the technical computing software Mathematica by Wolfram Research. Please see the help center to find out about the topics that can be asked here.
If this question can be reworded to fit the rules in the help center, please edit the question.

  • 1
    $\begingroup$ I don't get your results. However, have a read of Euler's formula from complex analysis and you see that the $e^{i n x}$ are evaluating to either 1, 0, or -1 in your formulas. $\endgroup$ – Edmund Jul 25 '16 at 10:04
  • $\begingroup$ @Edmund, I edit it for the output.when i calculate manually, the result suppose include I.why?. $\endgroup$ – munirah Jul 25 '16 at 11:30
  • $\begingroup$ what is the logic behind incrementing t by timeused?? $\endgroup$ – george2079 Jul 25 '16 at 11:55
  • $\begingroup$ @george2079, actually, I want to see the changes of the value when I increase the time by used time provided by computer system. From my reading, timeused is time given by computer. But why the I is not included in the output? $\endgroup$ – munirah Jul 25 '16 at 12:11
  • 3
    $\begingroup$ I'm voting to close this question as off-topic because the problem seems to stem from a possible misunderstanding of the underlying math, and not from the code. $\endgroup$ – MarcoB Jul 25 '16 at 13:24

I am putting it as an answer just to remove this question from the unanswered queue.

Table[{x, Exp[I x] // N}, {x, 0, Pi, Pi/2}] // TableForm

$ \begin{array}{cc} 0 & 1. \\ \frac{\pi }{2} & 0.\, +1. i \\ \pi & -1. \\ \end{array} $


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