I need to perform certain operations on individual transfer functions. As an example,


Now I extract the required transfer functions, say $P_1$ and $P_2$


Now I want to perform an operation like $\Gamma=P_2 (P_1)^{-1}$. So I use


This gives me an error saying the first argument cannot be interpreted as a polynomial matrix in SystemsModelSeriesConnect[#1,#2]

I have tried writing it as $P_2.Inverse[P_1]$ but I cannot make it accept the argument. Additionally, I would need to do a lot of algebraic operations with the TransferFunctionModel which not always can be done with commands like SystemsModelSeriesConnect,SystemsModelParallelConnect, etc.

As you would have guessed, I am not too adept with the syntax in Mathematica, so please bear with my questions.

  • $\begingroup$ Could you give an example for your system? $\endgroup$
    – Phab
    Commented Jul 20, 2016 at 6:10
  • $\begingroup$ As far as I know, Inverse[] works only on square matrices. $\endgroup$
    – Phab
    Commented Jul 20, 2016 at 6:16

1 Answer 1


I don't know, if this is what you want. But you might try this:

P1 = SystemsModelExtract[Tfsys, {1}, {1}]
P2 = SystemsModelExtract[Tfsys, {1}, {2}]

P3 = TransferFunctionModel[Inverse[P1[s]], s]

T = SystemsModelSeriesConnect[P2, P3]

How I did get this:

Documentation says:

Inverse[m] gives the inverse of a square matrix m.

And because

someTF = TransferFunctionModel[1/s, s]


transfer function

where the first one is a transfer function model, but the second one is mixed. It's 1/someTFmodel.

You have to get the inner of your transfer function model, invert it, and put it back into a transfer function model. Helpful for this is documentation's TransferFunctionModel section "Properties & Relations":


  • $\begingroup$ How did you know it...it doesnt show up in the documentation...Can you give me a reasoning or insight into solving such issues? I seem to get in these minor issues a lot $\endgroup$
    – Zero
    Commented Jul 20, 2016 at 7:47
  • $\begingroup$ See my edit. Just click a bit around in the documentation, very often the solution is there, you just can't see it :) $\endgroup$
    – Phab
    Commented Jul 20, 2016 at 8:28
  • $\begingroup$ Really appreciate the response...cheers! $\endgroup$
    – Zero
    Commented Jul 20, 2016 at 9:24

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