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How to define the following matrix in Mathematica?

$$A(n) = \begin{pmatrix} B_{1} & B_{2} & \cdots & B_{n} & 1 \\ B_{n} & B_{1} & \cdots & B_{n-1} &1 \\ \vdots & \vdots & \ddots & \vdots \\ B_{2} & B_{3} & \cdots & B_{1} & 1\\ A_{1} & A_{2} & \cdots & A_{n} &1 \end{pmatrix}$$

For instance :

for $n=4$

Table[Subscript[B, k], {k, 1, 4}]

$$A(4) = \begin{pmatrix} B_{1} & B_{2} & B_{3} & B_{4}&1 \\ B_{4} & B_{1} & B_{2} & B_{3}&1 \\ B_{3} & B_{4} & B_{1} & B_{2}&1 \\ B_{2} & B_{3} & B_{4} & B_{1}&1 \\ A_{1} & A_{2} & A_{3} & A_{4}&1 \end{pmatrix}$$

how to define $A(n)$ as a function of $n$?

And then I wanna manipulate $A(n)$

Manipulate[A[n], {n, 2, 30}]

Thank you in advance to any one who may be able to give me some ideas

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1 Answer 1

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Three possibilities:

With[{n = 4}, 
     ArrayFlatten[{{NestList[RotateRight, Array[B, n], n - 1], 1}, {{Array[A, n]}, 1}}]]

With[{n = 4}, 
     ArrayFlatten[{{ToeplitzMatrix[RotateRight[Reverse[Array[B, n]]], 
                                   Array[B, n]], 1}, {{Array[A, n]}, 1}}]]

With[{n = 4}, 
     PadRight[Append[NestList[RotateRight, Array[B, n], n - 1], Array[A, n]],
              {n + 1, n + 1}, 1]]
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  • $\begingroup$ +1. But, can you use Subscript[B, n] $B_{n}$ instead $B[n]$? Manipulate[ ArrayFlatten[{{ToeplitzMatrix[RotateRight[Reverse[Array[B, n]]], Array[B, n]], 1}, {{Array[A, n]}, 1}}] // MatrixForm, {n, 2, 5, 1}] // TraditionalForm see here $\endgroup$
    – vito
    Jun 23, 2016 at 19:29
  • 1
    $\begingroup$ You can replace Array[B, n] with the appropriate call to Table[] and Subscript[]. $\endgroup$ Jun 23, 2016 at 19:30

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